Write the equation of the line that passes through the points (8, -1) and (2,-5) in standard form, giverslope form is y+1 = (x-8)

Answer:2x - 3y = 19Step-by-step explanation:The formula of a slope:[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]We have the points (8, -1) and (2, -5). Substitute:[tex]m=\dfrac{-5-(-1)}{2-8}=\dfrac{-4}{-6}=\dfrac{2}{3}[/tex]The point-slope form of an equation of a line:[tex]y-y_1=m(x-x_1)[/tex]Substitute:[tex]y-(-1)=\dfrac{2}{3}(x-8)[/tex][tex]y+1=\dfrac{2}{3}(x-8)[/tex] → the point-slope formConvert to the standard form: [tex]Ax+By=C[/tex][tex]y+1=\dfrac{2}{3}(x-8)[/tex]        multiply both sides by 3[tex]3y+3=2(x-8)[/tex]         use the distributive property a(b+c) = ab+ ac[tex]3y+3=2x-16[/tex]      subtract 3 from both sides[tex]3y=2x-19[/tex]       subreact 2x from both sides[tex]-2x+3y=-19[/tex]       change the signs[tex]2x-3y=19[/tex] → the standard form