MATH SOLVE

4 months ago

Q:
# NEED HELP ASAP PLEASE AND THANK YOU

Accepted Solution

A:

Answer:[tex] (x + 4)^2 + (y - 1)^2 = 81 [/tex]Step-by-step explanation:The standard of the equation of a circle is:[tex] (x - h)^2 + (y - k)^2 = r^2 [/tex] where point (h, k) is the center of the circle, and r is the radius of the circle.You need to complete the square for x and y.[tex] 8x + x^2 - 2y = 64 - y^2 [/tex]Move all variables to the left side by addition or subtraction.[tex] x^2 + 8x + y^2 - 2y = 64 [/tex]To complete a square, you need the square of half of the x or y term coefficient.For x: 1/2 * 8 = 4; 4^2 = 16For y: (1/2) * (-2) = -1; (-1)^2 = 1We add 16 to complete the square in x and 1 to complete the square in x. We must add those numbers to both sides of the equation.[tex] x^2 + 8x + 16 + y^2 - 2y + 1 = 64 + 16 + 1 [/tex][tex] (x + 4)^2 + (y - 1)^2 = 81 [/tex]