PLEASE SHOW ALL WORK ASAP IF U DONT SHOW ALL WORK I WILL REPORT U!!!!!!Laura graphs these equations and finds that the lines intersect at a single point, ( 1.5, -1/5)EQUATION A: = -2y +6x=12 EQUATION B: 4x+12y=-12Which statement is true about the values x= 1.5 and y= -1.5A. They satisfy equation A but not equation BB. They satisfy equation B but not equation AC. They are the only values that make the equation true D. They show that the lines are perpendiculer

Answer:They are the only values that make the equation true  Step-by-step explanation:Equation A = [tex]-2y +6x=12[/tex]Equation B: [tex]4x+12y=-12[/tex]Intersection point (1.5,-1.5)Option  A. They satisfy equation A but not equation B[tex]-2y +6x=12[/tex]Substitute x = 1.5 and y = -1.5[tex]-2(-1.5) +6(1.5)=12[/tex][tex]12=12[/tex]Satisfied Equation A[tex]4x+12y=-12[/tex]Substitute x = 1.5 and y = -1.5[tex]4(1.5)+12(-1.5)=-12[/tex][tex]-12=-12[/tex]Satisfied Equation BThus Option A is Wrong.Option B. They satisfy equation B but not equation AOption B is wrong Proved AboveOption C :  They are the only values that make the equation true Since they are satisfying both the equations Hence Option C is true.Option  D. They show that the lines are perpendicular[tex]y = mx+c[/tex]Where m is the slopeEquation A = [tex]-2y +6x=12[/tex][tex]6x-12=2y[/tex][tex]\frac{6x-12}{2}=y[/tex][tex]3x-6=y[/tex]Thus the slope of equation A is 3 [tex]4x+12y=-12[/tex] [tex]4x-12=-12y[/tex] [tex]\frac{4x-12}{-12}=y[/tex] [tex]\frac{-x}{3}+1=y[/tex]Slope of equation B is [tex]\frac{-1}{3}[/tex]Two Lines are perpendicular if their slopes are sameThus Option D is wrong since slopes are different .Hence Option C is true:They are the only values that make the equation true